Answer:
A skilled broker will be right at 60% of time compared to 50%
Explanation:
Solution
Given that:
Now,
Let X be represented as = number of correct predictions/outcomes
X foll binomial distribution with n = 3 and p = 0.5 for broker who use a toss coin
Thus,
P(X = 3) = p^3 = 0.5^3 which gives us = 0.125
So,
For a skilled broker, Y goes with the binomial distribution with n = 3 and p is = 0.6
Then,
P(Y = 3) = 0.6^3 = 0.216
We can therefore conclude who is skilled broker by making large number of observations
Hence, we say that a skilled broker will be correct 60% of time compared to 50% .