Respuesta :
So base on the said question that you have given and the given in the problem, the answers to the remaining questions are the following:
B. cost of manufacturing of the 2nd piano that day is $2000
C. cost of manufacturing of the 11th piano that day is $2000
D. The variable cost would be $2000
B. cost of manufacturing of the 2nd piano that day is $2000
C. cost of manufacturing of the 11th piano that day is $2000
D. The variable cost would be $2000
The correct answers are:
(a) $5600
(b) $2000
(c) $2000
(d) $2000
Explanation:
The function will become:
C(x) = 2000x + 1600; --- (1)
Where
x represents the piano
C(x) represents the total cost.
(a) To find the cost of manufacturing 2 pianos, we need to put x = 2 in equation (1):
(1) => C(2) = 2000(2) + 1600
C(2) = $5600
Hence the cost for manufacturing 2 pianos is $5600.
(b) In order to find the manufacturing cost of 2nd piano on the same day, we need to find the cost of 1 piano and the cost of 2 pianos. Then subtract both those costs to get the manufacturing cost of the 2nd piano (on the same day). Therefore,
C(1) = 2000(1) + 1600 = $3600
C(2) = 2000(2) + 1600 = $5600
Cost of manufacturing the 2nd piano that day = C(2) - C(1) = $5600 - $3600 = $2000.
(c) In order to find the manufacturing cost of 11th piano on the same day, we need to find the cost of 10 piano and the cost of 11 pianos. Then subtract both those costs to get the manufacturing cost of the 11th piano (on the same day). Therefore,
C(10) = 2000(10) + 1600 = $21600
C(11) = 2000(11) + 1600 = $23600
Cost of manufacturing the 2nd piano that day = C(11) - C(10) = $23600 - $21600 = $2000.
(d) The variable cost is the cost that changes with the change in the variable. In the equation (C(x) = 2000x + 1600), the expression that changes with the change in variable is "2000x". The co-efficient (2000) of x is the variable cost in this case.
Hence the variable cost is $2000.
Information: 1600 is the equation is the fixed cost, and the total cost is equal to the sum of the fixed cost and the variable cost.
(a) $5600
(b) $2000
(c) $2000
(d) $2000
Explanation:
The function will become:
C(x) = 2000x + 1600; --- (1)
Where
x represents the piano
C(x) represents the total cost.
(a) To find the cost of manufacturing 2 pianos, we need to put x = 2 in equation (1):
(1) => C(2) = 2000(2) + 1600
C(2) = $5600
Hence the cost for manufacturing 2 pianos is $5600.
(b) In order to find the manufacturing cost of 2nd piano on the same day, we need to find the cost of 1 piano and the cost of 2 pianos. Then subtract both those costs to get the manufacturing cost of the 2nd piano (on the same day). Therefore,
C(1) = 2000(1) + 1600 = $3600
C(2) = 2000(2) + 1600 = $5600
Cost of manufacturing the 2nd piano that day = C(2) - C(1) = $5600 - $3600 = $2000.
(c) In order to find the manufacturing cost of 11th piano on the same day, we need to find the cost of 10 piano and the cost of 11 pianos. Then subtract both those costs to get the manufacturing cost of the 11th piano (on the same day). Therefore,
C(10) = 2000(10) + 1600 = $21600
C(11) = 2000(11) + 1600 = $23600
Cost of manufacturing the 2nd piano that day = C(11) - C(10) = $23600 - $21600 = $2000.
(d) The variable cost is the cost that changes with the change in the variable. In the equation (C(x) = 2000x + 1600), the expression that changes with the change in variable is "2000x". The co-efficient (2000) of x is the variable cost in this case.
Hence the variable cost is $2000.
Information: 1600 is the equation is the fixed cost, and the total cost is equal to the sum of the fixed cost and the variable cost.