A piano manufacturer has a daily fixed cost of $1600 and a marginal cost of $2000 per piano. Find the cost C(x) of manufacturing x pianos in one day.

Okay so I came up with this function so far for the problem: C(x) = 2000x+1600

Use your function to answer the following questions:
(a) On a given day, what is the cost of manufacturing 2 pianos?
I worked it out and came up with:
C(2) = 2000(2) +1600
C(2) = $5600

The next part is where I'm having trouble . . .
(b) What is the cost of manufacturing the 2nd piano that day?
(c) What is the cost of manufacturing the 11th piano that day?
(d) What is the variable cost?

Respuesta :

So base on the said question that you have given and the given in the problem, the answers to the remaining questions are the following:
B. cost of manufacturing of the 2nd piano that day is $2000
C. cost of manufacturing of the 11th piano that day is $2000
D. The variable cost would be $2000
The correct answers are:
(a) $5600
(b) $2000
(c) $2000
(d) $2000

Explanation:
The function will become:
C(x) = 2000x + 1600; --- (1)

Where
x represents the piano
C(x) represents the total cost.

(a) To find the cost of manufacturing 2 pianos, we need to put x = 2 in equation (1):

(1) => C(2) = 2000(2) + 1600
C(2) = $5600

Hence the cost for manufacturing 2 pianos is $5600.

(b) In order to find the manufacturing cost of 2nd piano on the same day, we need to find the cost of 1 piano and the cost of 2 pianos. Then subtract both those costs to get the manufacturing cost of the 2nd piano (on the same day). Therefore,

C(1) = 2000(1) + 1600 = $3600
C(2) = 2000(2) + 1600 = $5600

Cost of manufacturing the 2nd piano that day = C(2) - C(1) = $5600 - $3600 = $2000.

(c) In order to find the manufacturing cost of 11th piano on the same day, we need to find the cost of 10 piano and the cost of 11 pianos. Then subtract both those costs to get the manufacturing cost of the 11th piano (on the same day). Therefore,

C(10) = 2000(10) + 1600 = $21600
C(11) = 2000(11) + 1600 = $23600

Cost of manufacturing the 2nd piano that day = C(11) - C(10) = $23600 - $21600 = $2000.

(d) The variable cost is the cost that changes with the change in the variable. In the equation (C(x) = 2000x + 1600), the expression that changes with the change in variable is "2000x". The co-efficient (2000) of x is the variable cost in this case.

Hence the variable cost is $2000.
Information: 1600 is the equation is the fixed cost, and the total cost is equal to the sum of the fixed cost and the variable cost.