During batting practice, two pop flies are hit from the same location, 2 s apart. The paths are modeled by the equations h = -16t^2 + 56t and h = -16t^2 + 156t - 248, where t is the time that has passed since the first ball was hit. Explain how to find the height at which the balls meet. Then find the height to the nearest tenth.

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Answer:

2.5 seconds since the first ball was hit.

Step-by-step explanation:

The equations that model the heights are:

  • h = -16t² + 56t
  • h = -16t² + 156t - 248

When the balls meet, both heights are equal, therefore:

-16t² + 56t = -16t² + 156t - 248

-16t² + 56t + 16t² - 156t + 248 = 0

- 100t + 248 = 0

248 = 100t

248/100 = t

t = 2.48 ≈ 2.5

Answer:

40.5 is the answer therefore The balls meet at a height of  ⇒ 40.5 ft.

Step-by-step explanation:

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