Answer:
(fog)(x) means that we have the function f(x) evaluated in the function g(x), or f(g(x)).
So, if f(x) = x^3 + 1 and g(x) = x - 2.
we have:
a) (fog)(0) = f(g(0)) = (0 - 2)^3 + 1 = -8 + 1 = -7
b) (gof)(0) = g(f(0)) = (0^3 + 1) - 2 = -1
c) (fof)(1) = f(f(1)) = (1^3 + 1)^3 + 1 = 2^3 + 1 = 8 + 1 = 9
d) (gog)(1) = g(g(1)) = (1 - 2) - 2 = -1 -2 = -3
