Respuesta :
Answer:
(1)[tex]x+y\leq 200[/tex]
[tex]x>0, y> 0[/tex]
(2)[tex]8x+14y\leq 2000[/tex]
(3)From the graph, the coordinates of the four vertices are:
- (0,143)
- (0,0)
- (133, 67)
- (200,0)
(4)Profit Function: P(x,y)=2x+3y
(5)Maximum profit =$467
Step-by-step explanation:
Let the number of sneakers in stock =x
Let the number of sandals in stock =y
(1)The owner of the store estimates that she won't sell more than 200 shoes each month. Therefore, an inequality that represents the possible amount of shoes she can purchase each month is:
[tex]x+y\leq 200[/tex]
[tex]x>0, y> 0[/tex]
(2)She does not plan to invest more than $2,000 on the inventory of the shoes.
The store owner pays $8 for the sneakers and $14 for the sandals.
Therefore, an inequality that represents how many sneakers and sandals she has in stock each month is:
[tex]8x+14y\leq 2000[/tex]
(3)From the graph, the coordinates of the four vertices are:
- (0,143)
- (0,0)
- (133, 67)
- (200,0)
(4)The sneakers can be sold for $10 and the sandals can be sold for $17.
Profit on one sneaker =$10-8=$2
Profit on one sandal =$17-14=$3
Profit Function: P(x,y)=2x+3y
(5)
At (0,143), Profit =2x+3y=2(0)+3(143)=$429
At (0,0), Profit =2x+3y=2(0)+3(0)=$0
At (133, 67), Profit =2x+3y=2(133)+3(67)=$467
At (200,0), , Profit =2x+3y=2(200)+3(0)=$400
Her maximum profit will be $467 when she sells 133 sneakers and 67 sandals.