Complete Question
The probability distribution table is given below:
[tex]\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|[/tex]
Answer:
1.61
Step-by-step explanation:
The probability distribution table is given below:
[tex]\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|[/tex]
We want to determine the mean number of times a person gave blood.
Expected Value, [tex]E(x)=\sum x_i\cdot P(x_i)[/tex]
[tex]=(0 \times 0.33)+ (1 \times 0.24)+(2\times0.16)+(3\times0.12)+(4\times0.08)+(5\times0.05)+(6\times0.02)\\=0+0.24+0.32+0.36+0.32+0.25+0.12\\=1.61\\[/tex]
The mean number of times a person gave blood based on this survey is 1.61.
