Answer:
[tex]a = 30[/tex]
[tex]b = 40[/tex]
Step-by-step explanation:
Given
The attached triangle
Such that K is parallel to L
Required
Find the value of a and b
From the properties of parallel triangles;
Provided that k is parallel to l, then
[tex]\frac{a}{40} = \frac{a+15}{60}[/tex]
Multiply both sides by (60)(40)
[tex](60)*(40)*\frac{a}{40} = (60)*(40)*\frac{a+15}{60}[/tex]
[tex]60a = 40(a+15)[/tex]
Open Bracket
[tex]60a = 40*a+40*15[/tex]
[tex]60a = 40a+600[/tex]
Subtract 40a from both sides
[tex]60a - 40a = 40a - 40a + 600[/tex]
[tex]20a = 600[/tex]
Divide both sides by 20
[tex]\frac{20a}{20} = \frac{600}{20}[/tex]
[tex]a = \frac{600}{20}[/tex]
[tex]a = 30[/tex]
Similarly;
[tex]\frac{b}{40} = \frac{b+20}{60}[/tex]
Multiply both sides by (60)(40)
[tex](60)*(40)*\frac{b}{40} = (60)*(40)*\frac{b+20}{60}[/tex]
[tex]60b = 40(b+20)[/tex]
Open Bracket
[tex]60b = 40*b+40*20[/tex]
[tex]60b = 40b+800[/tex]
Subtract 40b from both sides
[tex]60b - 40b= 40b - 40b + 800[/tex]
[tex]20b= 800[/tex]
Divide both sides by 20
[tex]\frac{20b}{20} = \frac{800}{20}[/tex]
[tex]b = \frac{800}{20}[/tex]
[tex]b = 40[/tex]
