Answer:
B have 5 more cranes than Ava.
Step-by-step explanation:
As per question statement:
Number of cranes with Ava = 100
Number of cranes with B = [tex]\frac{3}{4}[/tex] of the paper cranes that Ava has
[tex]\therefore[/tex] Number of cranes with B = [tex]\frac{3}{4}\times 100 =75[/tex]
Now, let us proceed step by step.
Step 1: Ava gave [tex]\frac{9}{20}[/tex] of her cranes to B:
i.e. [tex]\frac{9}{20} \times 100 = 5 \times 9 =45[/tex] cranes given to B
Now, number of cranes with Ava = 100 - 45 = 55
Number of cranes with B = 75 + 45 = 120
Step 2: B gave [tex]\frac{1}{4}[/tex] of her paper cranes to Ava:
i.e. [tex]\frac{1}{4} \times 120 = 30[/tex] cranes given to B
Now, number of cranes with Ava = 55 + 30 = 85
Number of cranes left with B = 120 - 30 = 90
So, the answer is:
Number of cranes that B have more than that of Ava = 90 - 85 = 5
