Answer:
12 cm
Explanation:
Given that: AB = 6 cm, BC = 6 cm, CD = 6 cm.
Point M divides AB into two equal parts, so that'
AM = MB = 3 cm
Also, point N divides CD into two equal parts, so that;
CN = ND = 3 cm
Therefore, distance between the midpoints M and N of segments AB and CD is given as;
MN = MB + BC + CN
= 3 + 6 + 3
= 12
Thus, the distance between the midpoints MN is 12 cm.