Respuesta :
Answer:
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
Step-by-step explanation:
6x^10 − 96x^2
Factor out 6x^2
6x^2 ( x^8 - 16)
Notice that inside the parentheses we have the difference of squares
6x^2 ( x^4 ^2 - 4^2) a^2 - b^2 = (a-b) (a+b)
6x^2 ( x^4 -4) (x^4 +4)
Notice that x^4-4 is also the difference of squares
6x^2 ( x^2^2 -2^2) (x^4 +4)
6x^2 ( x^2 -2) ( x^2 +2) (x^4 +4)
Note also that x^4 + 4 can be factored into (x^2+2x+2)(x^2-2x+2)
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
The maximum common factor is 6x², and the two factorizations are:
[tex]6*x^{10} - 96*x^2 = 6*x^2*( x^8 - 16) = 6*x^2*(x - \sqrt[8]{16})^4*(x + \sqrt[8]{16})^4[/tex]
How to factorize the given expression?
Here we have the expression:
[tex]6*x^{10} - 96*x^2[/tex]
First, we know that 96/6 = 16
Then we can write the factor [tex]6x^2[/tex] as the maximum common factor between the two terms.
Then we can rewrite:
[tex]6*x^{10} - 96*x^2 = 6*x^2*( x^8 - 16)[/tex]
To completely factorize the expression we factorize the part inside the parenthesis.
[tex]x^8 - 16\\\\x = \pm \sqrt[8]{16}[/tex]
Then we can write:
[tex]6*x^{10} - 96*x^2 = 6*x^2*( x^8 - 16) = 6*x^2*(x - \sqrt[8]{16})^4*(x + \sqrt[8]{16})^4[/tex]
If you want to learn more about factorization:
https://brainly.com/question/11579257
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