Answer:
0.253 m/s
Step-by-step explanation:
radius r of the circular rise = 13 mm = 0.013 m
apparent weight loss = 50%
acceleration of the new weight = 0.5 x 9.81 = 4.905 m/s^2
centripetal acceleration = 9.81 - 4.905 = 4.905 m/s^2
centripetal acceleration = [tex]\frac{v^{2} }{r}[/tex]
where v is the acceleration at the rise and r is the radius of the rise
centripetal force = [tex]\frac{v^{2} }{r}[/tex] = [tex]\frac{v^{2} }{0.013}[/tex]
4.905 = [tex]\frac{v^{2} }{0.013}[/tex]
[tex]v^{2}[/tex] = 0.063765
v = [tex]\sqrt{0.063765}[/tex] = 0.253 m/s
