Answer:
[tex]a_n=\dfrac{1}{2n-1}[/tex]
Step-by-step explanation:
Given the sequence:
[tex]1, \frac{1}{3} , \frac{1}{5} , \frac{1}{7}, \frac{1}{9}, \cdots[/tex]
We observe that the numerator is always 1.
In the denominator, for each nth term, the multiple of 2 decreases by 1.
We can, therefore, write the general term of the sequence as:
[tex]a_n=\dfrac{1}{2n-1}[/tex]