A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the peak current in this circuit is 0.8484 A, what is the impedance of this circuit

Respuesta :

Answer:

200 [tex]\Omega[/tex]

Explanation:

The computation of the impedance of the circuit is shown below:

Provided that

RMS voltage = 120 v

Frequency = 60.0 Hz

RMS current = 0.600 A

Based on the above information, the formula to compute the impedance is

[tex]Z=\dfrac{V_{max}}{I_{peak}}[/tex]

where,

[tex]V_{max} = \sqrt{2} \times V_{rms}[/tex]

[tex]= \sqrt{2} \times 120[/tex]

[tex]= 169.7 V[/tex]

And, [tex]I_Peak = 0.8484[/tex]

Now placing these above values to the formula

So, the impedance of the circuit is

[tex]= \frac{169.7}{0.8484}[/tex]

= 200 [tex]\Omega[/tex]