Answer:
The mass of the hailstone is [tex]m_2 = 0.05[/tex]
Explanation:
From the question we are told that
The mass of the hockey puck is [tex]m_1 = 0.2 \ kg[/tex]
The initial speed of the puck is [tex]u_1 = 10 \ m/s[/tex]
The final speed of the puck is [tex]v_f = 8 \ m/s[/tex]
According to the principles of linear momentum
[tex]m_1u_1 + m_2u_2 = (m_1 + m_2)v_f[/tex]
At initial the velocity of the hailstone was zero so
[tex]u_2 = 0 \ m/s[/tex]
So
[tex]m_1 u_1 = (m_1 + m_2 )v_f[/tex]
substituting values
[tex]0.2 * 10 = (0.2 + m_2 )* 8[/tex]
=> [tex]2 = (0.2 + m_2 )* 8[/tex]
=> [tex]0.25 = 0.2 + m_2[/tex]
=> [tex]m_2 = 0.05[/tex]
