Answer:
1 + root 5, 1 - root 5
Step-by-step explanation:
I assume you mean 3x^2-6x-12=0.
First, note that you can divide both sides by 3. You get:
x^2-2x-4=0
Use the quadratic equation.
[tex]x=\frac{2\pm\sqrt{4+16}}{2}=\frac{2\pm2\sqrt{5}}{2}=1\pm\sqrt{5}[/tex]
Therefore, x=1 + root 5, 1 - root 5