Respuesta :
Answer:
a) work done by external force = 7920.765 N
b) work done by gravity = 15141.735 J
c) 0 N
Explanation:
mass of box = 343 kg
weight of box = mass x acceleration due to gravity = 343 x 9.81 m/s^2 = 3364.83 N
length of incline = 9 m
angle of incline = 30°
external force = 5125 N
a) work done by external force
resultant force = external force - weight of box = 5125 - 3364.83 = 1760.17 N
work done by external force = resultant force x vertical distance up
work done by external force = 1760.17 x 9 sin 30° = 7920.765 N
b) work done by gravity = work done against gravity
length of incline = 9 m
we resolve to the vertical distance = 9 x sin 30° = 4.5 m
work done by gravity = weight of box x vertical height = 3364.83 x 4.5 = 15141.735 J
c) work done by the normal force
since there is no work done in the direction perpendicular to the plane, work done by the normal force = 0 N
a) The work done by external force is 7920.765 N
b) The work done by gravity is 15141.735 J
c) The work done by the normal force is 0 N
Calculation of work done by external force, gravity, and the normal force:
Since mass of box = 343 kg
Now we know that
weight of box = mass x acceleration
= 343 x 9.81 m/s^2
= 3364.83 N
Also, there is the length of incline = 9 m and angle of incline = 30°
Moreover, the external force = 5125 N
Now
a) work done by an external force is
resultant force = external force - weight of box
= 5125 - 3364.83
= 1760.17 N
Now work done should be
= resultant force x vertical distance up
= 1760.17 x 9 sin 30°
= 7920.765 N
b) work done by gravity = work done against gravity
Since length of incline = 9 m
So, the vertical distance = 9 x sin 30° = 4.5 m
Now work done by gravity is
= weight of box x vertical height
= 3364.83 x 4.5
= 15141.735 J
c) work done by the normal force
Here no work done should be done in the perpendicular direction so the work done should be zero N or 0 N
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