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A rigid massless rod is rotated about one end in a horizontal circle. There is a particle of mass m1 attached to the center of the rod and a particle of mass m2 attached to the outer end of the rod. The inner section of the rod sustains a tension that is 5 times as great as the tension that the outer section sustains. Find the ratio m1/m2

Respuesta :

Answer:

m₁/m₂ =8

Explanation:

Writing the centripetal force equation: where T₁ is inner tension and T₂ is outer tension

T₂ = m₂ × ω²R....equation 1

T₁-T₂ = m₁ × ω²R/2

Also T₁=5T₂

5T₂-T₂ = m₁ × ω²R/2

4 × 2T₂ = m₁ × ω²R

8T₂ = m₁ × ω²R

dividing it by equation 1

8 = m₁/m₂

Hence m₁/m₂ =8

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