A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ball is also thrown at the same speed horizontally at the wall, but sticks to it upon hitting. [THE CLAY BALL / THE RUBBER BALL /NEITHER] (circle one) exerts a greater magnitude of impulse on the wall. Briefly explain (either in words or calculations)

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okpalawalter8 okpalawalter8 · Answer 1 · 2020-07-05T02:53:02+02:00

Answer:

THE RUBBER BALL

Explanation:

From the question we are told that

The mass of the rubber ball is [tex]m_r = 2 \ kg[/tex]

The initial speed of the rubber ball is [tex]u = 3 \ m/s[/tex]

The final speed at which it bounces bank [tex]v - 3 \ m/s[/tex]

The mass of the clay ball is [tex]m_c = 2 \ kg[/tex]

The initial speed of the clay ball is [tex]u = 3 \ m/s[/tex]

The final speed of the clay ball is [tex]v = 0 \ m/s[/tex]

Generally Impulse is mathematically represented as

[tex]I = \Delta p[/tex]

where [tex]\Delta p[/tex] is the change in the linear momentum so

[tex]I = m(v-u)[/tex]

For the rubber is

[tex]I_r = 2(-3 -3)[/tex]

[tex]I_r = -12\ kg \cdot m/s[/tex]

=> [tex]|I_r| = 12\ kg \cdot m/s[/tex]

For the clay ball

[tex]I_c = 2(0-3)[/tex]

[tex]I_c = -6 \ kg\cdot \ m/s[/tex]

=> [tex]| I_c| = 6 \ kg\cdot \ m/s[/tex]

So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball