Answer:
[tex] \frac{y + 4}{y - 5} [/tex]
Option C is the correct option
Step-by-step explanation:
[tex] \frac{ {y}^{2} + 7y + 12}{ {y}^{2} - 2y - 15 } [/tex]
Write 7y as a sum
[tex] \frac{ {y}^{2} + 4y + 3y + 12}{ {y}^{2} - 2y - 15} [/tex]
Write -2y as a difference
[tex] \frac{ {y}^{2} + 4y + 3y + 12}{ {y}^{2} + 3y - 5y - 15} [/tex]
Factor out y from the expression
[tex] \frac{y(y + 4) + 3y + 12}{ {y}^{2} + 3y - 5y - 15 } [/tex]
Factor out 3 from the expression
[tex] \frac{y(y + 4) + 3(y + 4)}{ {y}^{2} + 3y - 5y - 15 } [/tex]
factor out y from the expression
[tex] \frac{y(y + 4) + 3(y + 4)}{y(y + 3) - 5y - 15} [/tex]
Factor out -5 from the expression
[tex] \frac{y(y + 4) + 3(y + 4)}{y(y + 3) - 5( y + 3)} [/tex]
factor out y + 4 from the expression
[tex] \frac{(y + 4)(y + 3)}{y(y + 3) - 5(y + 3)} [/tex]
Factor out y + 3 from the expression
[tex] \frac{(y + 4)(y + 3)}{(y + 3)(y - 5)} [/tex]
Reduce the fraction with y + 3
[tex] \frac{y + 4}{y - 5} [/tex]
Hope this helps..
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