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Paul is a year older than his wife and they have two children who are also one year apart. Paul notices that on his birthday in 2011, the product of his age and his wife's age plus the sum of his children's ages is 2011. What would have been the result if he had done this calculation thirteen years before?

Respuesta :

Chegsnut36

Answer:

997

Step-by-step explanation:

Well let's find the square root of 2011 because Paul and his wife are about the same age.

[tex]\sqrt{2011}[/tex]

= 44.8

Paul is 45 and his wife is 44.

44 + 45 = 1980.

2011 - 1980

= 31

So the children are 15 and 16.

45 + 44 + 15 + 16

= 997

Paul and wife - 45 and 44

Children - 15 and 16

Thus,

13 years ago they would be 997.

Hope this helps :)

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