Answer:
[tex]\boxed{x = 8}[/tex]
Step-by-step explanation:
For NO ║ KJ, The two triangles must be similar and their sides must be proportional.
So, the proportion of their sides is:
=> [tex]\frac{x-4}{x} = \frac{x-3}{x+2}[/tex]
Cross Multiplying
[tex]\sf x (x-3)= (x-4)(x+2)\\Multiplying\\x^2-3x = x^2+2x-4x-8\\x^2-3x = x^2-2x-8\\Subtracting\ x^2\ to \ both \ sides\\ -3x = -2x -8\\Adding \ 2x\ to\ both\ sides\\-3x+2x = -8\\-x = -8\\[/tex]
x = 8
So, For x = 8, NO will be parallel to KJ.