Answer:
72.96
Step-by-step explanation:
Let the first circle's radius be r and quarter circle's radius be R
Area of circle = π[tex]r^{2}[/tex]
= 3.14 × 8 × 8
= 200.96 [tex]cm^{2}[/tex]
Area of quarter circle = π[tex]R^{2}[/tex]/4
= 3.14 × 16 × 16
= 803. 84/4
=200.96
Area of shaded portion = (Area of Quarter circle - Area of semi-circle ACD - Area of triangle ABC) + (Area of the circle - Area of semi-circle ACD - Area of triangle ABC)
Area of Semi-circle = Area of the circle divided by 2
= 100.48
Area of triangle = [tex]\frac{bh}{2}[/tex]
= [tex]\frac{16 * 8}{2}[/tex]
= 64
Therefore, The area of shaded portion= (200.96-100.48-64) + (200.96 - 100.48 - 64)
= 36.48 +36.48
=72.96
