Answer:
1.67 s
Explanation:
Since the clock is moving at relativistic speed, the period dilates. So, we use the equation
t = t₀/√[1 - (v/c)²].
Given that t = the period of the clock = 1 s and v = speed of the clock = 0.80c, substituting these values into t, we have
t = t₀/√[1 - (v/c)²]
t = 1/√[1 - (0.8c/c)²]
t = 1/√[1 - (0.8)²]
t = 1/√[1 - 0.64]
t = 1/√0.36
t = 1/0.6
t = 1.67 s
So the period of the clock when it is observed while moving with a speed of 0.8c is 1.67 s
