Answer:
[tex]V=23.5L[/tex]
Explanation:
Hello,
In this case, it is convenient to compute the car's mileage in km/L as follows:
[tex]25.0\frac{mi}{gal}*\frac{1km}{0.6214mi}*\frac{1gal}{3.78L}=10.64\frac{km}{L}[/tex]
In such a way, since the distance is measured to be 250 km, the volume requirement is:
[tex]V=\frac{250km}{10.64kg/L}\\ \\V=23.5L[/tex]
Regards.