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A tree is 4 1/2 feet tall. It is expected to grow 1 3/4 feet per year. At this growth rate, how many years will it take for the tree to have a height greater then 40 feet?

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Answer:

21 years

Step-by-step explanation:

Given

[tex]Initial\ Height = 4\frac{1}{2}[/tex]

[tex]Final\ Height = 40[/tex]

[tex]Difference = 1\frac{3}{4}[/tex]

Required

Determine the years it'll take to grow to the final height

This question depicts arithmetic progression and will be solved using

[tex]T_n = a + (n - 1)d[/tex]

Where

[tex]T_n = 40[/tex]

[tex]a = 4\frac{1}{2}[/tex]

[tex]d = 1\frac{3}{4}[/tex]

Substitute these values in the given formula;

[tex]40 = 4\frac{1}{2} + (n - 1)1\frac{3}{4}[/tex]

Convert all fractions to decimal

[tex]40 = 4.5 + (n - 1) * 1.75[/tex]

Open Brackets

[tex]40 = 4.5 + 1.75n - 1.75[/tex]

Collect Like Terms

[tex]1.75n = 40 - 4.5 + 1.75[/tex]

[tex]1.75n = 37.25[/tex]

Divide both sides by 1.75

[tex]n = \frac{37.25}{1.75}[/tex]

[tex]n = 21.2857142857[/tex]

[tex]n = 21[/tex] (Approximated)

The number of years it will take for the tree to have a height greater than 40 feet is 23 years

Given:

Height of the tree = 4 1/2 feet

Growth rate per year = 1 3/4 feet

Expected growth rate = 40 feet

Expected Number of years = y

The inequality:

4 1/2 + 1 3/4y > 40

Subtract 4 1/2 from both sides

1 3/4y > 40 - 4 1/2

7/4y > 40 - 9/2

7/4y > (80-9)/ 2

7/4y > 79/2

divide both sides by 7/4

y > 79/2 ÷ 7/4

y > 79/2 × 4/7

y > (79×4) ) (2×7)

y > (316) / 14

y > 22.57142857142857

Approximately,

y > 23 years

Therefore, number of years it will take for the tree to have a height greater than 40 feet is 23 years

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