Plug in [tex]k-1[/tex] to each [tex]x[/tex] in the function.
[tex]f(k-1)=5(k-1)^2+4(k-1)-5[/tex]
[tex]f(k-1)=5(k^2-2k+1)+4k-4-5[/tex]
[tex]f(k-1)=5k^2-10k+5+4k-4-5[/tex]
[tex]f(k-1)=5k^2-6k-4[/tex]
Hope this helps.
頑張って!
f(k-1) = 5k² - 4k - 4
The given function is:
f(x) = 5x² + 4x - 5
To find f(k-1), substitute x = k-1 into f(x)
f(k-1) = 5(k-1)² + 4(k-1) - 5
f(k-1) = 5(k² - 2k + 1) + 4k - 4 - 5
f(k -1) = 5k² - 10k + 5 + 4k -9²
Collect like terms
f(k-1) = 5k² - 10k + 5k + 5 - 9
Simplify
f(k-1) = 5k² - 4k - 4
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