Respuesta :
The complete question is;
In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?
Answer:
2.185 × 10^(14) electrons/seconds
Explanation:
We are given current as 35 μA = 35 × 10^(-6) Amperes
The value of the charge on one electron is; e = 1.602 × 10^(-19) coulombs
Now, from conversions;
One ampere = one coulomb/second =
Then, 35 × 10^(-6) Ampere's would give;
35 × 10^(-6) Coulombs/sec
Now,
1.602 × 10^(-19) coulombs = 1 electron
Thus;
35 × 10^(-6) Coulombs/sec gives;
(35 × 10^(-6))/(1.602 × 10^(-19)) = 2.185 × 10^(14) electrons /sec
The average number of electrons per second that flow past a fixed reference cross-section perpendicular to the direction of flow is 2.185 × 10⁻¹⁴ electrons /sec
The flow of charge:
The question is as given below:
In electronic circuits, it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross-section that is perpendicular to the direction of flow?
Given information:
Current I = 35 μA = 35 × 10⁻⁶ A
charge on electron e = 1.602 × 10⁻¹⁹C
We know that:
I = de/dt, rate of flow of charge.
1A = 1C/s
Thus,
35 × 10⁻⁶ A = 35 × 10⁻⁶ C/s
Now, one electron has a charge of 1.602 × 10⁻¹⁹C
So, the number of electrons for a current of 35 × 10⁻⁶ C/s will be:
n = (35 × 10⁻⁶ C/s) ÷ (1.602 × 10⁻¹⁹C)
n = 2.185 × 10⁻¹⁴ electrons /sec
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