Answer:
A. (40⋅1/1+3)+(40⋅2/2+3)
Step-by-step explanation:
Given that:
[tex]\sum \limits ^2 _{k=1} \dfrac{40 \ k }{k + 3}[/tex]
which can be expressed as:
=[tex]\dfrac{40\times 1 }{1 + 3} + \dfrac{40\times 2 }{2 + 3}[/tex]
=[tex]\dfrac{40 }{4} + \dfrac{80 }{5}[/tex]
= [tex]10+ 16[/tex]
= 26
∴
[tex]\sum \limits ^2 _{k=1} \dfrac{40 \ k }{k + 3} = 26[/tex]
