Answer:
The domain of g(x) is -3 to infinity
Step-by-step explanation:
Given
[tex]g(x) = \sqrt{x + 3}[/tex]
Required
Determine the domain of g(x)
We start by expressing the content of the square root in the following form:
[tex]x + 3 \geq 0[/tex]
Subtract 3 from both sides
[tex]x + 3 -3 \geq 0 - 3[/tex]
[tex]x \geq 0 - 3[/tex]
[tex]x \geq - 3[/tex]
This can be expressed using interval notation as follows:
[tex]\{x: -3, infiniti\}[/tex]
Hence, the domain of g(x) is -3 to infinity
