Answer:
Answer: Option D.
Step-by-step explanation:
Hey there!!
Here, To find the equation of a st.line passing through point (3,1) is :
[tex](y - 1) = m1(x - 3)[/tex]
It is the first equation.
Given, Another equation is:
[tex]y = \frac{2}{3} x + 1[/tex]
It is 2nd equation.
Comparing the 2nd equation with y = mx+c we get,
Slope (m2) = 2/3.
As per the condition of parallel lines,
m1 = m2 = 2/3.
Putting, the value of m1 in equation 1st we get,
[tex](y - 1) = \frac{2}{3} (x - 3)[/tex]
or, 3 (y-1) = 2(x-3)
or, 3y - 3 = 2x - 6
[tex]y = \frac{2x - 6 + 3}{3} [/tex]
[tex]y = \frac{2}{3} x - 1[/tex]
Diving-3/3 = -1.
Therefore, y = 2/3 x - 1 is the required equation.
Hope it helps.
