Respuesta :

ZJSG09112007

Answer:

y =3x+10

Step-by-step explanation:

[tex]\mathrm{Line\:passing\:through\:}\left(1,\:13\right)\mathrm{,\:}\left(-2,\:4\right)\\\\(1,13)=(x_1,y_1)\\(-2,4) = (x_2,y_2)\\\\\frac{y-13}{x -1} = \frac{4-13}{-2-1}\\ \\\frac{y-13}{x-1} = \frac{-9}{-3}\\\\ -3(y-13)=-9(x-1)\\\\-3y +39 =-9x +9\\\\-3y =-9x+9-39\\\\-3y =-9x -30\\\\\frac{-3y}{-3} = \frac{-9x}{-3} - \frac{30}{-3} \\\\y = 3x+10[/tex]

jamieanomie

Answer:

 y - 4 = 3 ( x + 2 )

Step-by-step explanation:

so ,

( 1 , 13 )   and    ( - 2 , 4 )

x1   y1                 x2   y2

formulae of slope m is y2-y1

                                     over

                                     x2-x1

4-13

  /

-2-1

-9/-3

therefore m=3

now to get the equation of line is

y-y1=m(x-x1)

y - 13 = 3 ( x -  1 )

y - 13 = 3 x - 3

y = 3 x - 3 + 13

y = 3 x + 10

y - 4 = 3 x + 6

y - 4 = 3 ( x + 2

Otras preguntas