Answer:
j(x) is an odd function
Step-by-step explanation:
We are given;
j(x) = 220/x³ and j(-x) = 220/(-x)³
Now,
when x = 1;
j(x) = 220/1³ = 220/1 = 220
j(-x) = 220/(-1)³ = 220/-1 = -220
When x = 2;
j(2) = 220/2³ = 220/8
j(-2) = 220/(-2)³ = -220/8
Now, Algebraically, function j would be even if and only if j(-x) = j(x) for all x in the domain of j. While j is odd if and only if j(-x) = -j(x) for all x in the domain of j.
From the values gotten, we can see that :j(-x) = -j(x). Thus, we can say that j(x) is an odd function.
