Answer:
199
Step-by-step explanation:
So we have three consecutive numbers that totals 600 when added.
Let's let the first number be n.
This means that the next number is (n+1), and the subsequent number is (n+2).
This totals 600. In other words:
[tex](n)+(n+1)+(n+2)=600[/tex]
To solve for the integers, solve for n.
Combine like terms:
[tex]3n+3=600[/tex]
Subtract 3 from both sides:
[tex]3n=597[/tex]
Divide both sides by 3:
[tex]n=199[/tex]
So, the first integer is 199.
So our sequence is: 199, 200, 201.
So, the least of the three is 199.
And we're done!
