Answer:
Explanation:
According to hardy weinberg
p+q=1
p2+2pq+q2=1
p stands for the dominant genotype
q stands for recessive genotype
pq stands for population that are not homogenous i.e not the same
Given that p=0.3
P2=0.09
q=1-0.3= 0.7
q2=0.49
2pq= 2×0.3×0.7
=0.42
Therefore, the frequency of heterozygous population is 0.42
p2+2pq+q2
0.09+0.42+0.49 = 1
