contestada

The perimeter of rectangle is 48 cm. Find the sides of the rectangle if one of the sides is 12 cm longer than the other.
PLZ Hurry!!!
PLZ SHOW WORK
THX

Respuesta :

Bella616
L=W+12
2L+2W=48
2(W+12)+2W=48
2W+24+2W=48
4W=48-24
4W=24
W=24/4
W=6 ANS. FOR THE WIDTH.
L=6+12=18 ANS. FOR THE LENGTH.
PROOF:
2*18+2*6=48
36+12=48
48=48

Hope this helps:)

Answer:

The length is 18 Cm

The Width Is 6 Cm

Step-by-step explanation:

Write an equation

so perimeter is

2L+2W=P

In this case the perimeter is 48 and one side is 12 cm longer so let’s make the unknown side W, and L as 12+w since the longer side is 12cm longer then the unknown side.

Equation:

2(12+W)+2W=48

Combine like terms and solve the equation

24+4W=48 (I distributed then combined like terms)

Subtract 24 on both sides

4W=24

Isolate the variable by dividing 4 on both sides

W=6

Check:

2(12+6)+2(6)=48?

24+12+12=48✔️

Otras preguntas