Respuesta :
Answer:
The correct answer is B is false
Explanation:
This problem highlights the difference between vectors (speed) and scalars (speed)
average speed is defined by
v = Δx / Δt
bold indicates vectors
the average speed is
v= Δx / Δt
Let's calculate
first runner
Δt = Δx / v₁
Δt = 120/6
Δt = 20 s
Second runner
Δt₁ = dx1 / v2
Δt₁ = 60 / 7.5
Δt₁ = 8 s
v₂ = 0
Δt₂ = 4 s
Δt₃ = dx₃ / v₂
Δt₃ = 60 / 7.5
Δt₃ = 8 s
the displacement is Dx = 60 + 60 = 120 m
time is t_total = Δt₁ + Δt₂ + Δt₃
the average speed is
v = Dx / Dt
v = 120 / (8 + 4 + 8)
v = 6 m / s
speed has the same value
third runner
Δt₁ = 60/12
Δt₁ = 5 s
Get back to the finish line
Δt₂ = (-60) / (- 12)
Δt₂ = 5 s
Δt₃ = 120/12
Δt₃ = 10 s
The displacement (vector) is
dx = 60 -60 + 120
dx = 120
Time is t_total = Δt₁ + Δt₂ + Δt₃
veloicity is
v = dx / t_total
v = 120 / (5 + 5+ 10)
v = 6 m / s
the radidity is
the distance (scalar) traveled
dx = 60 +60 + 120
dx = 240 m
time t_total = dt1 + dt2 + dt3
the speed
v = 240 / (20)
v = 12 m / s
with these results we can review the final statements
a) True The speed is twice the speed
b) False The velocity is 6 m / s
c) True the speeds from the three runners are equal
d) True the speeds of all runners are equal
The correct answer is B is false