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The value for ψ in root tissue was found to be -1.6 bars. If you place the root tissue in a 0.1 m solution of sucrose at 20°c in an open beaker, what is the ψ of the solution, and in which direction would the net flow of water be? (hint: remember your formula: ψs = -icrt & your pressure constant, r = 0.0831 liters bars/ m k)

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danialamin

Answer:

[tex]\Psi=\Psi_s+\Psi_p\\[/tex]

[tex]I=1;C=0.1;R=0.0831\\[/tex]

[tex]T=20+273=293~C\\[/tex]

as beaker is open so

[tex]\Psi_p=0\\[/tex]

[tex]\Psi=\Psi_s\\\Psi=-2.43483[/tex]

As ψof solution is lower than the root tissue so water will move out of the root to the solution

Explanation:

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