Triangle D F E is shown. Lines are drawn from each point to the opposite side to form right angles. The lines intersect at point K. All side lengths are congruent.
[Figure may not be drawn to scale]

In triangle DFE, KJ = 50 units. What is the length of segment EK?

25 units
50 units
100 units
150 units

Question

contestada

Respuesta :

queenyxxx queenyxxx · Answer 1 · 2020-10-05T07:14:05+02:00

Answer:

I believe the answer is 100 units :)

Answer Link

abidemiokin abidemiokin · Answer 2 · 2021-11-13T10:49:39+01:00

The length of the segment EK from the triangle DFE is 100 units. Option C is correct.

Find the sketch of the diagram attached. From the diagram, we can see that the lines intersect to form a point K known as the centroid.

From the figure, the following expression is true;

EK : KJ = 2:1

[tex]\frac{EK}{KJ} = \frac{2}{1}\\EK = 2KJ[/tex]

Given the following parameter

KJ = 50 units

Substitute into the expression above to have:

EK = 2(50)

EK = 100 units

Hence the length of the segment EK from the triangle DFE is 100 units

Learn more here: https://brainly.com/question/25392294