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A circle in the xy-plane is represented by the equation [tex](x-4)^2+(y-4)^2=c[/tex], where [tex]c[/tex] is a constant. If (0, 0) is a point on this circle, what is the value of [tex]c[/tex]?

Respuesta :

Wolfyy

Answer:

32 = c

Step-by-step explanation:

We are given the point (0, 0). This means that is what we will substitute for x and y.

(x - 4)² + (y - 4)² = c

(0 - 4)² + (0 - 4)² = c

-4² - 4² = c

16 + 16 = c

32 = c

Best of Luck!

mhanifa

Answer:

  • c = 32

Step-by-step explanation:

Given the equation of circle:

  • (x - 4)² + (y - 4)² = c

And the point on same circle (0, 0)

Finding the value of c by considering the coordinates of the given point in the equation

  • (x - 4)² + (y - 4)² = c
  • (0 - 4)² + (0 - 4)² = c
  • ( -4)² + (- 4)² = c
  • 16 + 16 = c
  • 32 = c
  • c = 32

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