contestada

Marco is looking for a used sports car,
He wants to buy the one with the greatest
acceleration. Car A can go from 0 m/s to 17.9 m/s
in 4.0 s; car B can accelerate from 0 m/s to 22.4 m/s
in 3.5 s; and car C can go from 0 to 26.8 m/s in
6.0 s. Rank the three cars from greatest acceleration
to least, specifically indicating any ties.

Respuesta :

12153muffin

Answer:

The other one is wrong. It’s actually B,A,C

Explanation:

The order from greatest acceleration to least:

[tex]6.4 m/s^2 > 4.467 m/s^2> 4.475 m/s^2[/tex]

Given:

  • Car A can accelerate from 0 m/s to 17.9 m/s  in 4.0 s
  • Car B can accelerate from 0 m/s to 22.4 m/s  in 3.5 s
  • Car C can accelerate from 0 to 26.8 m/s in  6.0 s

To find:

Rank the three cars from greatest acceleration  to least

Solution:

  • Car A can go from 0 m/s to 17.9 m/s.

Initial velocity = u = 0 m/s

Final velocity = v = 17.9 m/s

Time atken = 4.0 s

Using first equation of motion:

[tex]v=u+at\\\\17.9 m/s=0 m/s+a\times 4.0 s\\\\a=\frac{17.9 m/s}{4.0 s}=4.475 m/s^2[/tex]

  • Car B can go from 0 m/s to 22.4 m/s.

Initial velocity = u = 0 m/s

Final velocity = v = 22.4 m/s

Time atken = 3.5 s

Using first equation of motion:

[tex]v=u+at\\\\22.4 m/s=0 m/s+a\times 3.5s\\\\a=\frac{22.4m/s}{3.5s}=6.4m/s^2[/tex]

  • Car C can go from 0 m/s to 26.8 m/s.

Initial velocity = u = 0 m/s

Final velocity = v = 26.8 m/s

Time atken = 6.0 s

Using first equation of motion:

[tex]v=u+at\\\\26.8 m/s=0 m/s+a\times 6.0 s\\\\a=\frac{26.8m/s}{6.0 s}=4.467m/s^2[/tex]

The order from greatest acceleration to least:

[tex]6.4 m/s^2 > 4.467 m/s^2> 4.475 m/s^2[/tex]

Learn more about acceleration here:

brainly.com/question/2437624?referrer=searchResults