What is the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)?
y minus (negative 3) = negative 4 (x minus 1)
y minus 1 = negative 4 left-bracket x minus (negative 3) right-bracket
Negative 1 minus y 1 = negative 4 (negative 3 minus x 1)
3 minus y 1 = negative 4 (1 minus x 1)

Respuesta :

Answer:

y-1= -4(x-(-3))

y minus 1 = negative 4 left-bracket x minus (negative 3) right-bracket

Step-by-step explanation:

The formula for point slope form is written: [tex]y-y_{1} = m(x-x_{1})[/tex]. Now we fill in our know information. m=-4 (because that is the slope), [tex]y_{1}[/tex]=1 (It is the y value in the ordered pair), [tex]x_{1}[/tex]= -3 (It is the x value in the ordered pair).

y-1=-4(x- (-3))

Answer:

y minus 1 = negative 4 left-bracket x minus (negative 3) right-bracket

Explanation:

I got it right.

Hope this Helps!