What is the acceleration of a vehicle that changes its velocity from 100 km/h to a dead stop in 30 s ? Answer in units of m/s 2 .

Respuesta :

Answer:

a = [tex]-\frac{25}{27}[/tex] m/s²

Explanation:

Acceleration (a) = (final velocity - initial velocity) ÷ (final time - initial time) =  [tex]\frac{v_{f} - v_{i} }{t_{f} - t_{i} }[/tex]

Converting the speed from km/h to m/s;

100 km = 100000m

1hr = 3600s

∴ 100km/hr ⇄ [tex]\frac{100000 m}{3600 s}[/tex] = [tex]\frac{250}{9} m/s[/tex]

Acceleration = [tex]\frac{0 - 250/9}{30}[/tex] = [tex]-\frac{250}{9 * 30} = -\frac{25}{27}[/tex] m/s²

i.e deceleration = [tex]\frac{25}{27}[/tex] m/s²