A block weighing (Fg) 50 N is resting on a steel table (us =0.74). The minimum force to start this block moving is __N.

Respuesta :

Answer:

F = 37 N

Explanation:

The minimum force required to move the block must be equal to the static frictional force between the block and the table. This force is given as:

F = Frictional Force

F = μs R

where,

F = Force required to move the block  = ?

μs = Coefficient of static friction = 0.74

R = Normal Reaction of the Block = Weight of the Block = 50 N

Therefore,

F = (0.74)(50 N)

F = 37 N

Answer:37

Explanation: