Answer:
The correct option is A) 3 square inches; [tex]2x^2-7x+6[/tex].
Step-by-step explanation:
It is given that the length of the frame is (2x-3) and the width is (x-2)
The area of the rectangle is: [tex]A=l\times w[/tex]
Where, A is the area l is the length and w is the width of the rectangle.
Put [tex]l=(2x-3)[/tex] and [tex]w=(x-2)[/tex] in the area of the rectangle.
[tex]A=(2x-3)(x-2)\\A=2x^2-4x-3x+6\\A=2x^2-7x+6[/tex]
The area of the frame expressed as a polynomial is [tex]2x^2-7x+6[/tex].
Now substitute x=3 in [tex]A=2x^2-7x+6[/tex].
[tex]A=2(3)^2-7(3)+6\\A=18-21+6\\A=3[/tex]
The area of the frame is 3 square inches.
Hence, the correct option is A) 3 square inches; [tex]2x^2-7x+6[/tex].
