Answer:
A. 0.0233
Explanation:
according to the equation,
no. of moles of KBrO3 : no. of moles of Br2 = 1 : 3
no. of moles of KBrO3
= ⅓ × 0.0700mol
= 0.0233 (3 sig. fig.)
The moles of KBrO₃ are required to prepare 0.0700 moles of Br₂ according to the given reaction is 0.023 moles.
Stoichiometry of the reaction gives idea about the amount of entities present before and after the completion of chemical reaction.
Given balanced chemical reaction is:
KBrO₃ + 5KBr + 6HNO₃ → ️6KNO₃ + 3Br₂ + 3H₂O
From the stoichiometry of the reaction, it is clear that:
3 moles of Br₂ = produced from 1 mole of KBrO₃
0.07 moles of Br₂ = produced from 1/3×0.07=0.023 moles of KBrO₃
Hence required moles of KBrO₃ is 0.023 moles.
To know more about stoichiometry, visit the below link:
https://brainly.com/question/24892067
