Answer:
Fencing needed = 20.8 units
Step-by-step explanation:
From the figure attached,
Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).
We have to find the length of fence required to cover the triangular garden.
Amount of fencing required = Perimeter of the triangular garden
Perimeter of the garden = AB + BC + AC
Formula to get the distance between A and B,
d = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
AB = [tex]\sqrt{(0-6)^2+(6-5)^2}[/tex] = [tex]\sqrt{37}[/tex]
BC = [tex]\sqrt{(6-5)^2+(5+1)^2}[/tex] = [tex]\sqrt{37}[/tex]
AC = [tex]\sqrt{(0-5)^2+(6+1)^2}[/tex] = [tex]\sqrt{74}[/tex]
Perimeter = [tex]\sqrt{37}+\sqrt{37}+\sqrt{74}[/tex]
= 6.08 + 6.08 + 8.60
= 20.76
≈ 20.8 units
Therefore, amount of fencing required to cover the triangular park is 20.8 units.
