contestada


What is the equation of the line that passes through the point
(5,-2) and has a slope of 6/5

Respuesta :

Answer:

y = [tex]\frac{6x}{5}[/tex] - 8

Step-by-step explanation:

given slope m = [tex]\frac{6}{5}[/tex]

point (5, -2) for (x1, y1)

equation for point slope form

y - y1 = m(x- x1)

y - (-2) = [tex]\frac{6}{5}[/tex] (x -5)

y + 2 = [tex]\frac{6}{5}[/tex]x - 6, simplify

y = [tex]\frac{6x}{5}[/tex] - 8,

further you can multiply by 5 to get rid of fraction

5y = 6x - 40