Answer:
Solve
1
Distribute
3
+
6
(
−
2
)
=
6
0
3y+{\color{#c92786}{6(y-2)}}=60
3y+6(y−2)=60
3
+
6
−
1
2
=
6
0
3y+{\color{#c92786}{6y-12}}=60
3y+6y−12=60
2
Combine like terms
3
+
6
−
1
2
=
6
0
{\color{#c92786}{3y}}+{\color{#c92786}{6y}}-12=60
3y+6y−12=60
9
−
1
2
=
6
0
{\color{#c92786}{9y}}-12=60
9y−12=60
3
Add
1
2
12
12
to both sides of the equation
9
−
1
2
=
6
0
9y-12=60
9y−12=60
9
−
1
2
+
1
2
=
6
0
+
1
2
9y-12+{\color{#c92786}{12}}=60+{\color{#c92786}{12}}
9y−12+12=60+12
4
Simplify
Add the numbers
Add the numbers
again
9
=
7
2
9y=72
9y=72
5
Divide both sides of the equation by the same term
9
=
7
2
9y=72
9y=72
9
9
=
7
2
9
\frac{9y}{{\color{#c92786}{9}}}=\frac{72}{{\color{#c92786}{9}}}
99y=972
6
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
8
y=8
y=8
Solution
=
8
Step-by-step explanation:
y=8