Answer: 1068
Step-by-step explanation:
Formula of sample size :
[tex]n=p(1-p)(\dfrac{z^c}{E})^2[/tex] , where p = prior population proportion , E = margin of error , [tex]z^c[/tex] = Critical z- value.
Let p = proportion of visitors who are repeat visitors.
Given : p=0.5
E= 3%= 0.03
critical z-value for 95% confidence = 1.96
Now, [tex]n=(0.5)(1-0.5)(\dfrac{1.96}{0.03})^2[/tex]
[tex]=0.25(65.33)^2\\\\=0.25(4268.0089)=1067.002225\approx1068[/tex] [round to the next integer]
Hence, the required sample size = 1068
