Let's solve the exponential equation 4ex = 80. (a) First, we isolate ex to get the equivalent equation Correct: Your answer is correct. . (b) Next, we take ln of each side to get the equivalent equation Incorrect: Your answer is incorrect. . (c) Now we use a calculator to find x ≈ 2.996 Correct: Your answer is correct. . (Round your answer to three decimal places.)

Respuesta :

Answer:

The solution of the exponential equation [tex]4e^{x} = 80[/tex] is

x = 2.996

Step-by-step explanation:

To solve the exponential equation [tex]4e^{x} = 80[/tex]

First, we will isolate [tex]e^{x}[/tex] by dividing both sides of the equation by 4, so that we get

[tex]\frac{4e^{x}}{4} = \frac{80}{4}[/tex]

[tex]e^{x} = 20[/tex]

Now, we will take the ln of both sides of the equation to get

[tex]ln(e^{x}) =ln(20)[/tex]

(NOTE: [tex]ln(e^{x}) = x[/tex] )

Then,

[tex]x =ln(20)[/tex]

[tex]x = 2.9957[/tex]

∴ x = 2.996 (to three decimal places)

Hence, the solution of the exponential equation [tex]4e^{x} = 80[/tex] is

x = 2.996

Exponential equations are represents as: [tex]\mathbf{ae^x = n}[/tex]

The approximated value of x is 2.996

The equation is given as:

[tex]\mathbf{4e^x = 80}[/tex]

(a) Isolate e^x

To do this, we divide both sides by 4

[tex]\mathbf{e^x = 20}[/tex]

(b) Take ln of both sides

This given

[tex]\mathbf{ln(e^x) = ln(20)}[/tex]

This gives

[tex]\mathbf{x = ln(20)}[/tex]

(c) Using a calculator

Using a calculator, we have:

[tex]\mathbf{ ln(20) \approx 2.996}[/tex]

So, we have:

[tex]\mathbf{ x \approx 2.996}[/tex]

Hence, the approximated value of x is 2.996

Read more about exponential equations at:

https://brainly.com/question/11672641